PAT 乙级 1012 数字分类

解题思路:此题不难，但是烦在格式繁琐，需要注意的点特别多

c语音版

#include<stdio.h>
int main()
{
	int a1=0,a2=0,a5=0;
	int count[6]={0};
	double a4=0;
	int n;
	scanf("%d",&n);
	int num;
	int flag=1;
	while(n--)
	{
		scanf("%d",&num);
		if(num%10==0)
		{
			count[1]++;
			a1+=num;		
		}
		if(num%5==1)
		{
			count[2]++;
			a2+=flag*num;
			flag=-flag;
		}
		if(num%5==2)
		{
			count[3]++;
		}
		if(num%5==3)
		{
			count[4]++;
			a4+=num;
		}
		if(num%5==4&&num>a5)
		{
			count[5]++;
			a5=num;
		}
	 } 
	 if(count[1])
	 printf("%d",a1);
	 else
	 printf("N");
	 int i;
     for(i=2;i<=5;i++)
     {
     	if(count[i]==0)
     	{
     		printf(" N");
     		continue;
		 }
		 else
		 switch(i)
		 {
		 	case 2: printf(" %d",a2);break;
			case 3: printf(" %d",count[3]);break;
			case 4: printf(" %.1f",a4*1.0/count[4]);break;
			case 5: printf(" %d\n",a5);break; 	 	
		 }
	 }
	return 0;
}